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      <text>12.2.2.4 point of inflection</text>
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      <text><![CDATA[<h5>Conclusion following previous exercise</h5>
<p>Using this analysis we cannot decide whether the stationary point at \(x=0\) is a local maximum, minimum or a point of inflection. However, just to the left of \(x=0\) the value of \(\dfrac{\mathrm{d}f}{\mathrm{d}x}\) (which equals \(x^2(4x-1)\)) is negative
    whilst just to the right of \(x=0\) the value of \(\dfrac{\mathrm{d}f}{\mathrm{d}x}\) is negative again. Hence the stationary point at \(x=0\) is a <strong>point of inflection</strong>. This is confirmed by sketching the curve below.</p>
<figure class="HELM_figure"><img src="@@PLUGINFILE@@/12.2.6%20figure%2017.svg" alt="inflection at zero zero and minimum at x equals 1 over 4 and y equals minus zero point zero zero one three. " class="img-responsive atto_image_button_text-bottom" width="252" height="128"></figure>]]></text>
<file name="12.2.6 figure 17.svg" path="/" encoding="base64">[encoded data, 437732 characters]</file>
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